Jon Moxley height: How tall is Jon Moxley?

Jonathan David Good was born on December 7, 1985. Jonathan is a professional wrestler from the United States who is now affiliated with All Elite Wrestling (AEW), where he goes by the ring name Jon Moxley. Moxley is currently on his record-setting second reign as the AEW World Champion. Additionally, Good makes appearances for New Japan Pro-Wrestling (NJPW) and on the independent wrestling scene, primarily for Game Changer Wrestling (GCW), where he is currently the GCW World Champion during his first reign. Jon Moxley rose to fame in the WWE, where he competed from 2011 until 2019 under the ring name Dean Ambrose.

Jon Moxley height: How tall is Jon Moxley?

John Moxley stands a height of 6 feet 4 inches. In 2004, Good made Moxley debut in professional wrestling. Moxley competed in a number of regional promotions, including Heartland Wrestling Association (HWA), Westside Xtreme Wrestling (wXw), Full Impact Pro (FIP), Combat Zone Wrestling (CZW), and Dragon Gate USA, using the ring name Jon Moxley (DGUSA). Moxley assumed the moniker Dean Ambrose after signing with WWE in 2011 and started wrestling in the organization’s developmental divisions, Florida Championship Wrestling and NXT, before making his main roster debut in November 2012 as a part of The Shield with Roman Reigns and Seth Rollins. In May 2013, Ambrose won the WWE United States Championship, his first title in the company. His 351-day reign set a record for the longest reign of the title since it was placed under WWE’s control.

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